Q:
A six-cylinder, four-stroke diesel engine develops a power of 200 kW at 2000 revolution per minute. The brake specific fuel consumption is 0.3 kg / kW – h. What is the time for injection if the injection takes place over 20° crank angle?
| A) 1 millisecond
|
B) 2 milliseconds
|
| C) 1.5 milliseconds
| D) 1.66 milliseconds
|
Answer & Explanation
Answer: D) 1.66 milliseconds
Explanation: Power output / cylinder = 200 / 6 = 33.33 kW. Fuel consumption / cylinder = 33.33 * brake specific fuel consumption = 33.33 * 0.3 = 9.99 kg / h. Time for injection = (20 * 60) / (360 * 2000) = 1.667 * 10-3 sec = 1.66 milliseconds.
Answer
Explanation
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