Q:
A brass bar, having cross sectional area of 100mm2, is subjected to axial force of 50kN. The length of two sections is 100mm and 200mm respectively. What will be the total elongation of bar if E = 1.05 x 105 N/mm2 ?
Answer & Explanation
Answer: D) 1.428mm
Explanation: Elongation in section 1 = P/AE x L = 50,000/(100×1.05×100,000) x 100 = 0.476mm
Elongation In section 2 = P/AE x L = 50,000/(100×1.05×100,000) x 200 = 0.952mm
Total elongation = 0.476 + 0.952 = 1.428mm.
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