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Q:

A brass bar, having cross sectional area of 150mm˛, is subjected to axial force of 50kN. What will be the total strain of bar if E= 1.05 x 104 N/mm˛?

A) 0.062mm B) 0.025mm
C) 0.068mm D) 0.054mm
 
Answer & Explanation Answer: D) 0.054mm

Explanation: Strain in section 1 = P/AE = 50,000/(100×1.05×100,000) = 0.031mm
Strain In section 2 = P/AE = 50,000/(100×1.05×100,000) = 0.031mm
Resultant strain = 0.031 + 0.031 = 0.062mm.
Here the calculation of strain does not requires the value of lengths of the sections.

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