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Q:

Two shafts having an included angle of 150° are connected by a Hooke’s joint. The driving shaft runs at a uniform speed of 1500 r.p.m. The driven shaft carries a flywheel of mass 12 kg and 100 mm radius of gyration. Using the above data, calculate the maximum torque required in N-m.

A) 822 B) 888
C) 890 D) 867
 
Answer & Explanation Answer: A) 822

Explanation: ? = 180 -160 = 30?
cos2? = 2sin˛ ?/1-sin˛ ? = 0.66
angular acc = d?/dt
= 6853 rad/s˛
I = 0.12 Kg-m˛
Therefore max torque = I.ang acc.
= 822 N-m.

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Category: Mechanical Engineering MCQs
Sub Category: Theory of Machines Mcqs

61
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