Q:
What is the value of Refrigeration effect if m1 = 4 kg/min, and enthalpies for the point 1, 2, 4, 5, 9 are 1350, 1550, 1480, 1620, and 280 kJ/kg. If the refrigeration effect is 4280 kJ/min and work done is 15 kW, then what is the value of C.O.P.?
Answer & Explanation
Answer: C) 4.75
Explanation: Given: m1 = 4 kg/min
h1 = 1350 kJ/kg
hf9 = h10 = 280 kJ/kg
h2 = 1550 kJ/kg
h4 = 1480 kJ/kg
h5 = 1620 kJ/kg
As, enthalpies of all points is given but it is a redundant data cause direct values of refrigeration effect and work is given, hence C.O.P. can be found easily.
Refrigeration effect = m1 (h1 – h11)
= 4280 kJ/min
Work = 15 kW = 900 kJ/min
C.O.P. = Refrigeration effect / Work
= 4280 / 900
= 4.75.
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